
Here we will explain and find the remainder of the fraction 590/5.
We like this exercise, because we think math learners will better understand fractions in general by finding the remainder of fractions such as 590/5.
The fraction 590/5 has a numerator and denominator. The numerator is 590 (above the fraction line) and the denominator is 5 (below the fraction line).
Furthermore, the numerator (590) is the part and the denominator (5) is the whole. In other words, to create a whole you need 5 parts. In this case, you have 590 parts. So the question becomes, "How many wholes can you make with 590 parts and how many leftovers will you have?"
You can make a total of 118 wholes by using 590 parts. You can't make more wholes than that, because then you would go over 590 parts.
The difference between the parts you used to make as many wholes as possible, and how many parts you have total, is leftover parts. Furthermore, the leftover parts are the remainder of 590/5. Therefore the answer is 0.
Here is the math to clarify what we explained above:
5 fits fully 118 times into 590.
118 times 5 equals 590.
590 minus 590 = 0 remainder.
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