What is the remainder of 827/5?

Here we will explain and find the remainder of the fraction 827/5.

We like this exercise, because we think math learners will better understand fractions in general by finding the remainder of fractions such as 827/5.

The fraction 827/5 has a numerator and denominator. The numerator is 827 (above the fraction line) and the denominator is 5 (below the fraction line).

Furthermore, the numerator (827) is the part and the denominator (5) is the whole. In other words, to create a whole you need 5 parts. In this case, you have 827 parts. So the question becomes, "How many wholes can you make with 827 parts and how many leftovers will you have?"

You can make a total of 165 wholes by using 825 parts. You can't make more wholes than that, because then you would go over 827 parts.

The difference between the parts you used to make as many wholes as possible, and how many parts you have total, is leftover parts. Furthermore, the leftover parts are the remainder of 827/5. Therefore the answer is 2.

Here is the math to clarify what we explained above:

5 fits fully 165 times into 827.

165 times 5 equals 825.

827 minus 825 = 2 remainder.

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