What is the remainder of 837/5?

Here we will explain and find the remainder of the fraction 837/5.

We like this exercise, because we think math learners will better understand fractions in general by finding the remainder of fractions such as 837/5.

The fraction 837/5 has a numerator and denominator. The numerator is 837 (above the fraction line) and the denominator is 5 (below the fraction line).

Furthermore, the numerator (837) is the part and the denominator (5) is the whole. In other words, to create a whole you need 5 parts. In this case, you have 837 parts. So the question becomes, "How many wholes can you make with 837 parts and how many leftovers will you have?"

You can make a total of 167 wholes by using 835 parts. You can't make more wholes than that, because then you would go over 837 parts.

The difference between the parts you used to make as many wholes as possible, and how many parts you have total, is leftover parts. Furthermore, the leftover parts are the remainder of 837/5. Therefore the answer is 2.

Here is the math to clarify what we explained above:

5 fits fully 167 times into 837.

167 times 5 equals 835.

837 minus 835 = 2 remainder.

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