What is the remainder of 839/5?




Here we will explain and find the remainder of the fraction 839/5.

We like this exercise, because we think math learners will better understand fractions in general by finding the remainder of fractions such as 839/5.

The fraction 839/5 has a numerator and denominator. The numerator is 839 (above the fraction line) and the denominator is 5 (below the fraction line).

Furthermore, the numerator (839) is the part and the denominator (5) is the whole. In other words, to create a whole you need 5 parts. In this case, you have 839 parts. So the question becomes, "How many wholes can you make with 839 parts and how many leftovers will you have?"

You can make a total of 167 wholes by using 835 parts. You can't make more wholes than that, because then you would go over 839 parts.

The difference between the parts you used to make as many wholes as possible, and how many parts you have total, is leftover parts. Furthermore, the leftover parts are the remainder of 839/5. Therefore the answer is 4.


Here is the math to clarify what we explained above:

5 fits fully 167 times into 839.

167 times 5 equals 835.

839 minus 835 = 4 remainder.

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