What is the remainder of 845/3?

Here we will explain and find the remainder of the fraction 845/3.

We like this exercise, because we think math learners will better understand fractions in general by finding the remainder of fractions such as 845/3.

The fraction 845/3 has a numerator and denominator. The numerator is 845 (above the fraction line) and the denominator is 3 (below the fraction line).

Furthermore, the numerator (845) is the part and the denominator (3) is the whole. In other words, to create a whole you need 3 parts. In this case, you have 845 parts. So the question becomes, "How many wholes can you make with 845 parts and how many leftovers will you have?"

You can make a total of 281 wholes by using 843 parts. You can't make more wholes than that, because then you would go over 845 parts.

The difference between the parts you used to make as many wholes as possible, and how many parts you have total, is leftover parts. Furthermore, the leftover parts are the remainder of 845/3. Therefore the answer is 2.

Here is the math to clarify what we explained above:

3 fits fully 281 times into 845.

281 times 3 equals 843.

845 minus 843 = 2 remainder.

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