What is the remainder of 847/3?

Here we will explain and find the remainder of the fraction 847/3.

We like this exercise, because we think math learners will better understand fractions in general by finding the remainder of fractions such as 847/3.

The fraction 847/3 has a numerator and denominator. The numerator is 847 (above the fraction line) and the denominator is 3 (below the fraction line).

Furthermore, the numerator (847) is the part and the denominator (3) is the whole. In other words, to create a whole you need 3 parts. In this case, you have 847 parts. So the question becomes, "How many wholes can you make with 847 parts and how many leftovers will you have?"

You can make a total of 282 wholes by using 846 parts. You can't make more wholes than that, because then you would go over 847 parts.

The difference between the parts you used to make as many wholes as possible, and how many parts you have total, is leftover parts. Furthermore, the leftover parts are the remainder of 847/3. Therefore the answer is 1.

Here is the math to clarify what we explained above:

3 fits fully 282 times into 847.

282 times 3 equals 846.

847 minus 846 = 1 remainder.

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