What is the remainder of 941/5?

Here we will explain and find the remainder of the fraction 941/5.

We like this exercise, because we think math learners will better understand fractions in general by finding the remainder of fractions such as 941/5.

The fraction 941/5 has a numerator and denominator. The numerator is 941 (above the fraction line) and the denominator is 5 (below the fraction line).

Furthermore, the numerator (941) is the part and the denominator (5) is the whole. In other words, to create a whole you need 5 parts. In this case, you have 941 parts. So the question becomes, "How many wholes can you make with 941 parts and how many leftovers will you have?"

You can make a total of 188 wholes by using 940 parts. You can't make more wholes than that, because then you would go over 941 parts.

The difference between the parts you used to make as many wholes as possible, and how many parts you have total, is leftover parts. Furthermore, the leftover parts are the remainder of 941/5. Therefore the answer is 1.

Here is the math to clarify what we explained above:

5 fits fully 188 times into 941.

188 times 5 equals 940.

941 minus 940 = 1 remainder.

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